Command Line Escape Characters (WinZip)

[sean_walsh]

Hi

I have a zip file that is encrypted with a tricky password, which I
need to extract from a .bat file.

The password is: -33,33_(}33"33*33=33|33^%33

So I try this line in a .bat file:
"c:\program files\winzip\wzunzip.exe" -o -s-33,33_(}33"33*33=33|33^%33
MYZIP.zip C:\MYZIP\

This hits a problem because of the double-quote in the password.
"ERROR - missing closing quote on argument"

This also doesn't work:
-s"-33,33_(}33""33*33=33|33^%33"

I believe the ^ char is an escape character for DOS Command Line
arguments, but that doesn't work. I tried to simplify this by changing
the password temporarily to 33"33 and using the following arguments:
-s33^"33
-s"33^"33"

No luck. If I try this:
-s"33""33"

It DOES actually get passed, but it comes back with "Skipping xxxx -
the password is incorrect", even though if I use winzip through the
interface, it works.

Any ideas?

 

[Pegasus \(MVP\)]

Re: Command Line Escape Characters (WinZip)


"sean_walsh" <seanmatthewwalsh@hotmail.com> wrote in message
news:65387bf8-8f7d-4674-8c00-a34df5645af9@i76g2000hsf.googlegroups.com...
> Hi
>
> I have a zip file that is encrypted with a tricky password, which I
> need to extract from a .bat file.
>
> The password is: -33,33_(}33"33*33=33|33^%33
>
> So I try this line in a .bat file:
> "c:\program files\winzip\wzunzip.exe" -o -s-33,33_(}33"33*33=33|33^%33
> MYZIP.zip C:\MYZIP\
>
> This hits a problem because of the double-quote in the password.
> "ERROR - missing closing quote on argument"
>
> This also doesn't work:
> -s"-33,33_(}33""33*33=33|33^%33"
>
> I believe the ^ char is an escape character for DOS Command Line
> arguments, but that doesn't work. I tried to simplify this by changing
> the password temporarily to 33"33 and using the following arguments:
> -s33^"33
> -s"33^"33"
>
> No luck. If I try this:
> -s"33""33"
>
> It DOES actually get passed, but it comes back with "Skipping xxxx -
> the password is incorrect", even though if I use winzip through the
> interface, it works.
>
> Any ideas?
>

Some password . . . Try this command:
wzunzip.exe -o -s-33,33_(}33"33*33=33|33^%%33 MYZIP.zip C:\MYZIP\

 

[sean_walsh]

Re: Command Line Escape Characters (WinZip)

nope, no luck.

There seems to be a few problems: the ^ is a special char, the | is
too, and the " needs to be doubled up somehow.

I didnt realise % was too...

I tried:
-s-33,33_(}33"33*33=33|33^%%33
-s-33,33_(}33""33*33=33|33^%%33
-s-33,33_(}33"33*33=33^|33^^%%33
-s-33,33_(}33""33*33=33^|33^^%%33
-s-33,33_(}33^"33*33=33^|33^^%%33

no luck....

 

[Pegasus \(MVP\)]

Re: Command Line Escape Characters (WinZip)


"sean_walsh" <seanmatthewwalsh@hotmail.com> wrote in message
news:ae313e4e-c5b4-49aa-b73c-2798c4245373@34g2000hsh.googlegroups.com...
> nope, no luck.
>
> There seems to be a few problems: the ^ is a special char, the | is
> too, and the " needs to be doubled up somehow.
>
> I didnt realise % was too...
>
> I tried:
> -s-33,33_(}33"33*33=33|33^%%33
> -s-33,33_(}33""33*33=33|33^%%33
> -s-33,33_(}33"33*33=33^|33^^%%33
> -s-33,33_(}33""33*33=33^|33^^%%33
> -s-33,33_(}33^"33*33=33^|33^^%%33
>
> no luck....

As you have found out, there are several types of "poison" characters in
your password, namely ("|^%. While it may be possible to compose a string
that negates the interpreted meaning of each of them, it would be far more
productive to compose a password that avoids these characters. There are
numerous other special characters on the keyboard such as ~`!@#$*_-+={}[] -
use them instead!

 

[Newell White]

Re: Command Line Escape Characters (WinZip)


"sean_walsh" wrote:

> nope, no luck.
>
> There seems to be a few problems: the ^ is a special char, the | is
> too, and the " needs to be doubled up somehow.
>
> I didnt realise % was too...
>
> I tried:
> -s-33,33_(}33"33*33=33|33^%%33
> -s-33,33_(}33""33*33=33|33^%%33
> -s-33,33_(}33"33*33=33^|33^^%%33
> -s-33,33_(}33""33*33=33^|33^^%%33
> -s-33,33_(}33^"33*33=33^|33^^%%33
>
> no luck....
>
Sean,
Try running this .bat file

set mypass=3,3"3|3^3
echo %mypass%

Can't find a way to get % in the string though, maybe you can?
--
Regards,
Newell White