Index was outside the bounds of the array.

[I_R_Lee]

How would I avoid that error? It happens on this line of code:

            txtWord.Text = Replace$(txtWord.Text.Chars(I), txtWord.Text.Chars(I), "*")

Ive also tried

            txtWord.Text = Replace$(txtWord.Text, txtWord.Text.Chars(I), "*")

but I get the same error.
Any help?

 

[I_R_Lee]

Never mind, I just found the StringBuilder class, and that allows it!

 

[I_R_Lee]

Actually, I do need help.
I get that error on these lines instead:

        Dim SB As New System.Text.StringBuilder(CurWord)
        Dim SBW As New System.Text.StringBuilder(txtWord.Text)
        Dim SBG As New StringBuilder(txtGuess.Text)
        For I = 0 To SB.Length  Here
            If SB(I) = SBG(I) Then  Here
                txtWord.Text = Replace(SBW(I), SB(I), SBG(I), 1, I)  and here
            End If
        Next

How do I stop that? Or at least, how do you replace individual characters?

 

[Divil]

It should almost certainly be,

For I = 0 To SB.Length - 1

 

[I_R_Lee]

Thanks, that fixed the first line but the other two still give the same error.

 

[Derek Stone]

Youre trying to access elements of a variable which isnt an array.

 

[I_R_Lee]

Is there a way to replace individual characters
e.g

Dim This As String = "ThisThis"
Dim That As String = "ThatThat"
txtWord.Text = This & That
For I = 0 To txtWord.Text - 1
txtWord.Text = Replace(txtWord.Text, This.Chars(I), That.Chars(I+1))
Next

Something like that, is it possible, if not, how would it be done with the string builder class?

 

[Derek Stone]

Coerce the string into a byte array using System.Text.Encoding.GetBytes().