N
newmember1_29
Guest
This is for an advanced calculator, so when my input is sin 90 i want it to give me sin 90 degree = 1, but instead it gives me 0,88
Dim cosinus As Double
cosinus = Double.Parse(txtDisplay.Text)
cosinus = Math.Sin(cosinus * Math.PI / 180)
txtDisplay.Text = System.Convert.ToString(cosinus)
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Dim cosinus As Double
cosinus = Double.Parse(txtDisplay.Text)
cosinus = Math.Sin(cosinus * Math.PI / 180)
txtDisplay.Text = System.Convert.ToString(cosinus)
Continue reading...