A
ahmeddc
Guest
hi
I want to add a column with indexed property to ms access table programmatically.
my code
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim con As New OleDb.OleDbConnection("provider=microsoft.ace.oledb.12.0;data source=" & Application.StartupPath & "\test.accdb;Jet OLEDB
atabase Password=12345")
con.Open()
Dim dbSchema As DataTable = con.GetOleDbSchemaTable(OleDb.OleDbSchemaGuid.Tables, New Object() {Nothing, Nothing, "goodb", "TABLE"})
con.Close()
If dbSchema.Rows.Count > 0 Then
Else
Dim cmd As New OleDb.OleDbCommand("CREATE TABLE [" + "goodb" + "] ([ID] COUNTER NOT NULL,[Field1] varchar(50) indexed(Yes (No Duplicates)), [Field2] LongBinary, Primary Key([ID]) )", con)
con.Open()
cmd.ExecuteNonQuery()
MessageBox.Show("Table Created Successfully")
con.Close()
End If
End Sub
indexed property
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Continue reading...
I want to add a column with indexed property to ms access table programmatically.
my code
Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
Dim con As New OleDb.OleDbConnection("provider=microsoft.ace.oledb.12.0;data source=" & Application.StartupPath & "\test.accdb;Jet OLEDB

con.Open()
Dim dbSchema As DataTable = con.GetOleDbSchemaTable(OleDb.OleDbSchemaGuid.Tables, New Object() {Nothing, Nothing, "goodb", "TABLE"})
con.Close()
If dbSchema.Rows.Count > 0 Then
Else
Dim cmd As New OleDb.OleDbCommand("CREATE TABLE [" + "goodb" + "] ([ID] COUNTER NOT NULL,[Field1] varchar(50) indexed(Yes (No Duplicates)), [Field2] LongBinary, Primary Key([ID]) )", con)
con.Open()
cmd.ExecuteNonQuery()
MessageBox.Show("Table Created Successfully")
con.Close()
End If
End Sub
indexed property

Continue reading...