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Hello Every one,
I have a file which contains below text (Some times this file size may grow up to 200 MB)
<Test>.... </Test> 0x00 (Hexa decimal character)
<Test>.... </Test>
<Test>.... </Test>
Below code works fine when there is no Invalid characters and when there is a invalid character/Hexa decimal value it throws an exception at reader.ReadInnerXml(); saying " '.', hexadecimal value 0x00, is an invalid character. Line 1, position 658."
Can some one please help me in how i can remove special character or avoid exception or ignore special character.
try
{
string path = @"C:\Users\xxxxx\Desktop\Test.log";
var tmpFileStream = new FileStream(path, FileMode.Open, FileAccess.Read,
FileShare.ReadWrite);
//var memoryStream = new MemoryStream();
var xmlDoc = new XmlDocument();
var settings = new XmlReaderSettings { CheckCharacters = false, IgnoreWhitespace = true };
using (var reader = XmlReader.Create(new StreamReader(tmpFileStream), settings))
{
//tmpFileStream = null;
while (reader.Read())
{
if (reader.NodeType != XmlNodeType.Element || reader.Name != "Test") continue;
var innerXml = reader.ReadInnerXml();
}
}
}
catch (Exception ex)
{
}
Continue reading...
I have a file which contains below text (Some times this file size may grow up to 200 MB)
<Test>.... </Test> 0x00 (Hexa decimal character)
<Test>.... </Test>
<Test>.... </Test>
Below code works fine when there is no Invalid characters and when there is a invalid character/Hexa decimal value it throws an exception at reader.ReadInnerXml(); saying " '.', hexadecimal value 0x00, is an invalid character. Line 1, position 658."
Can some one please help me in how i can remove special character or avoid exception or ignore special character.
try
{
string path = @"C:\Users\xxxxx\Desktop\Test.log";
var tmpFileStream = new FileStream(path, FileMode.Open, FileAccess.Read,
FileShare.ReadWrite);
//var memoryStream = new MemoryStream();
var xmlDoc = new XmlDocument();
var settings = new XmlReaderSettings { CheckCharacters = false, IgnoreWhitespace = true };
using (var reader = XmlReader.Create(new StreamReader(tmpFileStream), settings))
{
//tmpFileStream = null;
while (reader.Read())
{
if (reader.NodeType != XmlNodeType.Element || reader.Name != "Test") continue;
var innerXml = reader.ReadInnerXml();
}
}
}
catch (Exception ex)
{
}
Continue reading...