I
I'm GNit
Guest
'm new for VS 2019. In my program, I'm getting error 5. Pls help to resolve it. I've attached the sample screen shot for ready reference.
In my application, I've 2 forms. First is Main Menu (MDI Parent) & 2nd is Parameter Form (MDI Chield). During execution, when I Select the Parameter form, immediately I'm getting the above attached error messages.
I'm new to the VB 2019, I downloaded community version (vs_community__433194754.1593179091) from Microsoft site and installed on my PC. Created new project with TWO forms. ONE as Main Form (MDI Parent) & SECOND as Parameter Form (MDI Child). In parameter form, I've used the following components:
1. SaveFileDialog (System.Windows.Forms.SaveFileDialog)
2. StatusStrip (System.Windows.Forms.StatusStrip)
3. OpenFileDialog (System.Windows.Forms.OpenFile.Dialog)
4. BackgroundWorker (System.ComponentModel.BackgroundWorker)
I believe, above said components are default components. Kindly guide, if any steps are left out.
Continue reading...
In my application, I've 2 forms. First is Main Menu (MDI Parent) & 2nd is Parameter Form (MDI Chield). During execution, when I Select the Parameter form, immediately I'm getting the above attached error messages.
I'm new to the VB 2019, I downloaded community version (vs_community__433194754.1593179091) from Microsoft site and installed on my PC. Created new project with TWO forms. ONE as Main Form (MDI Parent) & SECOND as Parameter Form (MDI Child). In parameter form, I've used the following components:
1. SaveFileDialog (System.Windows.Forms.SaveFileDialog)
2. StatusStrip (System.Windows.Forms.StatusStrip)
3. OpenFileDialog (System.Windows.Forms.OpenFile.Dialog)
4. BackgroundWorker (System.ComponentModel.BackgroundWorker)
I believe, above said components are default components. Kindly guide, if any steps are left out.
Continue reading...