Newbie : DFS : Why a physical root is required?

  • Thread starter Thread starter redheart27@rediffmail.com
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redheart27@rediffmail.com

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I have a fundamental question that is not directly answered anywhere,
hence I seek your help. I wish to understand the idea behind the
design. My intention is to learn.

This is how I (as a newbie) would expect DFS to be designed. (Assume a
Domain environment)
A DFS service runs on the DC/member servers. The namespace and other
configuration is replicated among these servers. The service will
listen to requests from clients and answer them by looking up its
data.

(a) As per the MS implementation, an empty physical directory
structure is created to represent the namespace. Why was this unusual
data representation chosen?

(b) Why does Active Directory(AD) duplicate the information of the DFS
root? In fact, why does AD get involved at all, except perhaps, to
provide the information for clients to locate the DFS servers?

Please help. Thanks.
 
Re: Newbie : DFS : Why a physical root is required?

HI,

> (a) As per the MS implementation, an empty physical directory
> structure is created to represent the namespace. Why was this unusual
> data representation chosen?

Otherwise the namespace was just the namespace, and you couldnt do anything
with it.

You cant make coffee on it, nor can you save files on it.
I'm sure you have no namespace, you can make coffee on it,
even if it was a java namespace, do you?

May be you could write the namespace down on paper.
Then for sure, one comes and asks, Why the hell did he involve paper with it
?

> (b) Why does Active Directory(AD) duplicate the information of the DFS
> root? In fact, why does AD get involved at all, except perhaps, to
> provide the information for clients to locate the DFS servers?

Isnt it a nice idea ? Saving you from running arround in your (later)
company,
making miles and miles every day with your cheat of paper holding your
namespace,
duplicating it to the other employees!

;-)
JK
 
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