Command .bat files and return code

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Mario - Roma

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I need to create a .bat file to performa some tests required by a third
party application.
The third party application documentation says that
"The script must exit with a 0 (zero) value to be considered
a success. Any other output results in failure. Upon success, the stdout
output of the
script will be examined."
I made some tests but I prseume I made some mistake.
Can anybody please explain how a .bat script must close in order to exit
with a 0 or a non 0 value and, maybe. provide some simple sample?
Regards
Mario
 
Re: Command .bat files and return code


"Mario - Roma" <mario@mydomain.local> wrote in message
news:uyyl63CHJHA.2156@TK2MSFTNGP05.phx.gbl...
>I need to create a .bat file to performa some tests required by a third
>party application.
> The third party application documentation says that
> "The script must exit with a 0 (zero) value to be considered
> a success. Any other output results in failure. Upon success, the stdout
> output of the
> script will be examined."
> I made some tests but I prseume I made some mistake.
> Can anybody please explain how a .bat script must close in order to exit
> with a 0 or a non 0 value and, maybe. provide some simple sample?
> Regards
> Mario

Error levels (=return codes) are generated by each command included in your
batch file. The batch file itself returns the error level of the last
command you run. You can therefore force a zero error level by making the
last command a "safe" command, e.g. like so:
@echo off
"c:\Some Folder\Some Program.exe"
cd

Line 2 in this batch file might generate a non-zero error level. However,
since Line 3 generates a zero error level, the batch file will return a zero
error level too.
 
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